Will #if RELEASE work like #if DEBUG does in C#?


In all the examples I've seen of the #if compiler directive, they use "DEBUG". Can I use "RELEASE" in the same way to exclude code that I don't want to run when compiled in debug mode? The code I want to surround with this block sends out a bunch of emails, and I don't want to accidentally send those out when testing.

3/9/2019 8:58:51 AM

Accepted Answer

No, it won't, unless you do some work.

The important part here is what DEBUG really is, and it's a kind of constant defined that the compiler can check against.

If you check the project properties, under the Build tab, you'll find three things:

  • A text box labelled "Conditional compilation symbols"
  • A check box labelled "Define DEBUG constant"
  • A check box labelled "Define TRACE constant"

There is no such checkbox, nor constant/symbol pre-defined that has the name RELEASE.

However, you can easily add that name to the text box labelled Conditional compilation symbols, but make sure you set the project configuration to Release-mode before doing so, as these settings are per configuration.

So basically, unless you add that to the text box, #if RELEASE won't produce any code under any configuration.

1/17/2019 6:54:47 AM

RELEASE is not defined, but you can use

#if (!DEBUG)

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